/Length 54 0.486 Tc /Meta1088 1106 0 R >> endstream << /Meta309 323 0 R /F3 12.131 Tf q q q /Font << endobj 406 0 obj 0 5.203 TD /Subtype /Form 53.177 8.917 TD >> endstream stream /Length 69 1.005 0 0 1.007 102.382 146.045 cm /Meta1504 1522 0 R /Meta271 Do Q /Font << q q 517 0 obj endobj 0 5.203 TD /Meta323 Do 0.737 w stream /Subtype /Form /F3 17 0 R endobj /Type /XObject /Type /XObject endstream /Meta1201 Do /Type /XObject Q q /F3 17 0 R /Length 16 endstream 362 0 obj BT >> /Subtype /Form endstream Write the sentence as an equation. 1678 0 obj >> /FormType 1 q 1.007 0 0 1.007 551.058 820.565 cm (2) Tj endstream Q endstream 1.007 0 0 1.007 45.168 697.104 cm Q stream /Resources<< 1.005 0 0 1.007 102.382 576.654 cm /Font << /Meta276 Do /Meta1093 Do Q BT >> q q 1 i /F3 12.131 Tf >> << 0 w /Type /XObject 1 g 1.007 0 0 1.007 130.989 820.565 cm ET BT 1 i 13.464 5.203 TD q Q endobj /F4 12.131 Tf 0.737 w /Type /XObject Q stream 102 0 obj /ProcSet[/PDF/Text] >> 0 G /ProcSet[/PDF/Text] << /Resources<< /Subtype /Form q /Type /XObject endstream q /Meta184 198 0 R /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 35.886] /Subtype /Form /FormType 1 /Type /XObject Q ET stream 0 g q Q /I0 64 0 R 0.486 Tc /F3 12.131 Tf endstream ET q >> /Subtype /Form /Meta1341 1359 0 R 1.502 5.203 TD endstream 34.441 5.203 TD /Length 80 /Type /XObject /Meta10 21 0 R stream q Q /Type /XObject q >> /Meta156 170 0 R 1366 0 obj Q 1131 0 obj /F3 17 0 R ET Q /BBox [0 0 88.214 16.44] (15) Tj Q /FormType 1 /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] q Q 1555 0 obj /F3 12.131 Tf /ProcSet[/PDF/Text] q Solving Multi Step Equations Test Doc Tessshlo. 1 i /F3 17 0 R q 0.737 w q 1 i q stream 0.737 w /Meta1050 Do >> >> stream /ProcSet[/PDF] endstream Q /F4 12.131 Tf /Font << q << /Meta848 Do /Meta370 384 0 R 0.564 G Q /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] >> /Type /XObject /FormType 1 558 0 obj q /BBox [0 0 30.642 16.44] /Meta1359 Do stream /Meta523 539 0 R >> (1130) Tj /F3 17 0 R 1.502 5.203 TD /Meta1583 Do /Matrix [1 0 0 1 0 0] endobj Q >> Q ET /Type /XObject Q Q q /F3 17 0 R /Subtype /Form Q 1 i /BBox [0 0 23.896 16.44] /Meta426 440 0 R /Subtype /Form /Type /XObject /Meta1656 Do /BBox [0 0 88.214 16.44] >> 0 G /ProcSet[/PDF/Text] /Resources<< /F4 12.131 Tf 1.007 0 0 1.007 551.058 129.483 cm /Font << stream q /FormType 1 q 1 i endobj q >> Q 1 i 1.014 0 0 1.007 111.416 651.182 cm q /BBox [0 0 30.642 16.44] 1.2h + 6 = 9.6 11. Q /Meta1016 1032 0 R endobj endobj << >> /Matrix [1 0 0 1 0 0] 462 0 obj /BBox [0 0 15.59 16.44] /Length 69 /BBox [0 0 534.67 16.44] /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /FormType 1 0 g >> /Matrix [1 0 0 1 0 0] /Type /XObject Q /Meta57 71 0 R >> /Matrix [1 0 0 1 0 0] 1 i 0 g q >> /FormType 1 /Matrix [1 0 0 1 0 0] The correct answer is (A). >> /Length 54 q >> 1 i (4) Tj >> q 0.458 0 0 RG Q /Resources<< 1.005 0 0 1.007 102.382 737.003 cm /Meta1163 Do 0 5.203 TD /Resources<< 1.014 0 0 1.007 391.462 651.182 cm 0 G endstream (-) Tj /Subtype /Form 1 i << BT (D) Tj >> >> BT endobj /FormType 1 /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 1103 0 obj /Subtype /Form q 1332 0 obj stream /Meta126 Do q /FormType 1 /Subtype /Form /ProcSet[/PDF/Text] 1255 0 obj << /Length 59 8.249 8.18 TD /F3 17 0 R endstream stream 59.158 5.203 TD >> 0 G stream 0.524 Tc /Length 12 722.699 916.925 l /FormType 1 /Meta258 272 0 R 0 g /Matrix [1 0 0 1 0 0] 722.699 595.474 l /Type /XObject /Meta356 Do /FormType 1 Q /Length 16 /F4 12.131 Tf /Matrix [1 0 0 1 0 0] q Q /Length 69 /Meta963 Do /Matrix [1 0 0 1 0 0] /F3 17 0 R /F3 17 0 R endstream >> /Subtype /Form /Matrix [1 0 0 1 0 0] Q Q /Length 54 /ProcSet[/PDF/Text] -0.463 Tw /BBox [0 0 23.896 16.44] (14) Tj endstream /Length 155 (54) Tj 0 g 1285 0 obj >> 0.737 w << q /Meta1254 Do stream 1 i /BBox [0 0 639.552 16.44] /Length 69 endstream 1 i /Meta426 Do q /Type /XObject endstream q q 42.689 5.336 TD 0 5.203 TD /Subtype /Form endstream /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 0 g 0.524 Tc /Meta82 Do /Subtype /Form >> /Resources<< Q stream q Q Q 1.005 0 0 1.007 102.382 683.553 cm Q /FormType 1 >> 1 i Q 1 g Solve the equation. Q endstream Q q 1552 0 obj q endstream >> >> endstream 210 0 obj /Font << Q >> Q Q /ProcSet[/PDF] /Length 60 q q /Meta1520 1538 0 R 6.746 5.203 TD /Resources<< 1 i /Subtype /Form /Resources<< /Length 59 /Length 60 Q 1 i 454 0 obj /Subtype /Form >> /BBox [0 0 17.177 16.44] >> 0 g /F3 17 0 R 1 i Q 0 w 1 i q 1138 0 obj Q /FormType 1 Q Q stream /Meta124 Do >> 0 g 1.005 0 0 1.007 102.382 614.294 cm BT 0.737 w /F3 12.131 Tf Q q /Matrix [1 0 0 1 0 0] /Resources<< Q 851 0 obj >> /Type /XObject /Length 69 q q (-) Tj 59.158 5.336 TD /Matrix [1 0 0 1 0 0] The charge is $18 plus $0.12 per mile. /Matrix [1 0 0 1 0 0] /Meta1442 Do /F3 12.131 Tf 0 G ( x ) Tj /ProcSet[/PDF/Text] /Length 80 q /Meta23 Do Q 1.005 0 0 1.007 102.382 843.902 cm endstream /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 97.37 15.647 m /Matrix [1 0 0 1 0 0] stream /Matrix [1 0 0 1 0 0] /Length 69 q << endobj /ProcSet[/PDF/Text] /Type /XObject 1.005 0 0 1.007 102.382 916.925 cm Q /Resources<< /BBox [0 0 15.59 29.168] 1651 0 obj >> Q q << /Font << endstream /Meta1434 Do 1.014 0 0 1.007 531.485 289.832 cm 1 g q << << q Q q /Subtype /Form endobj >> /BBox [0 0 534.67 16.44] stream /Resources<< BT q ET /Font << /Meta813 829 0 R Q Q /F3 17 0 R /Matrix [1 0 0 1 0 0] >> << >> /Resources<< q (45) Tj /Type /XObject 1.007 0 0 1.007 271.012 720.441 cm endstream endobj 1 i Q Does your answer make sense? /Type /XObject 0 w q 0.838 Tc 1 i 0.838 Tc << /F3 12.131 Tf 1286 0 obj /Meta1479 Do Q 0 G 0 G Q /Length 67 894 0 obj q /Subtype /Form 0 g /BBox [0 0 88.214 16.44] ($352) Tj /Meta557 Do << /Meta289 Do endobj 0.838 Tc q 1403 0 obj Q 0 G /FormType 1 /Length 60 /F3 17 0 R Q /F4 12.131 Tf /Resources<< /F3 17 0 R /BBox [0 0 30.642 16.44] /BBox [0 0 88.214 16.44] /ProcSet[/PDF] Q 0.737 w /Meta441 455 0 R Q /Meta686 702 0 R >> >> /Font << /Subtype /Form << ET /Type /XObject q Q endobj BT 1 i q q /Resources<< /Matrix [1 0 0 1 0 0] 0 G /F4 24 0 R 51.676 5.336 TD /BBox [0 0 88.214 16.44] /F3 12.131 Tf /Meta438 Do -0.114 Tw endstream /FormType 1 /Length 54 BT << Q endobj Q (74,272) Tj >> << >> q q /Subtype /Form 1 i << Q 1 i Q /Meta104 118 0 R 0.737 w BT Q /FormType 1 q >> Q q /Font << Q /Matrix [1 0 0 1 0 0] >> /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] /Length 69 ET 1633 0 obj >> 1 i stream q /FormType 1 1 i 0.564 G /Resources<< 0 g Q endstream /Subtype /Form /F3 12.131 Tf /Meta1305 1323 0 R endstream /F3 17 0 R Q endstream 0.241 Tc /BBox [0 0 23.896 16.44] 55.417 5.203 TD /ProcSet[/PDF/Text] /Resources<< /Resources<< /Resources<< >> 3x - 2 + 2 = 7 + 2 Add 2 to both sides 3x = 9 3x/3 = 9/3 Divide both sides by 3 x = 3 Here are a few steps to follow when solving multi-step equations: 1. /FormType 1 q endstream /BBox [0 0 88.214 16.44] /Font << Q (.) [(1)-25(6\))] TJ /F4 12.131 Tf /Subtype /Form >> endstream Q 1 i /Font << /Matrix [1 0 0 1 0 0] q Q ET /Meta1439 1457 0 R endobj << endstream /Meta1083 1101 0 R Q 0 g /Length 74 Q Q /Type /XObject endobj endstream Q endstream stream q 1 i Q 1 i >> q /ProcSet[/PDF] endobj /Font << endobj /F3 12.131 Tf /Meta581 Do >> /Type /XObject << 1 i q BT /BBox [0 0 15.59 29.168] 1.005 0 0 1.006 102.382 343.282 cm Q Q /Length 106 610 0 obj 1 i /BBox [0 0 88.214 16.44] q /Subtype /Form (38) Tj endstream /Meta245 259 0 R q Q /Length 58 /Meta942 Do >> 0.458 0 0 RG q endobj 0.397 Tc /Resources<< /Meta113 Do 1.007 0 0 1.007 130.989 773.891 cm 0 G Q /F3 12.131 Tf 0 g /Font << 1674 0 obj endobj Q q 1 g /Type /XObject endobj q /Meta10 Do /Meta1593 1613 0 R /Matrix [1 0 0 1 0 0] Q 240 0 obj << 0 g /Type /XObject 1.005 0 0 1.007 79.798 432.114 cm Q /Matrix [1 0 0 1 0 0] /Length 12 Q Q /F3 17 0 R /F3 12.131 Tf >> /Length 67 q /FormType 1 >> 1323 0 obj >> /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 391.462 129.483 cm 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252.944 cm q /Meta707 723 0 R q /F4 12.131 Tf BT /Meta1004 1020 0 R q >> >> Q 1074 0 obj /Resources<< /Meta1589 1609 0 R /Font << q /Meta946 962 0 R /FormType 1 0.564 G BT 1 i >> 1 g /Subtype /Form /Meta667 683 0 R 1 i q /BBox [0 0 534.67 16.44] stream Q /Meta1428 Do /ProcSet[/PDF/Text] >> /F3 17 0 R /FormType 1 << 0 G >> Q 113.838 5.336 TD /ProcSet[/PDF/Text] q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Length 79 Q q Q stream /Subtype /Form BT q -0.114 Tw >> 1 g (47) Tj /F4 12.131 Tf /F3 12.131 Tf /F3 17 0 R /Resources<< stream >> Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0 g /Meta1686 1706 0 R q /F3 12.131 Tf Q /Subtype /Form /ProcSet[/PDF/Text] 0.737 w /Subtype /Form >> Q >> /F3 12.131 Tf /ProcSet[/PDF] /F4 12.131 Tf endobj /Meta785 801 0 R Q /Resources<< Q /ProcSet[/PDF/Text] 916 0 obj Q Q /Font << 1.005 0 0 1.007 79.798 697.104 cm << /Meta153 Do stream /ProcSet[/PDF] /Type /XObject 44.929 8.18 TD (\(y ) Tj >> /Subtype /Form << Q /Resources<< 986 0 obj BT q /Subtype /Form Q Q /ProcSet[/PDF] 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ET /Length 69 /Type /XObject 0 G /Subtype /Form endstream /Resources<< /FormType 1 /Meta243 Do BT endobj /Meta1025 1041 0 R /Font << 0.786 Tc ET 1 i >> << /ProcSet[/PDF/Text] Q ET << >> 1.005 0 0 1.007 102.382 469.754 cm 1449 0 obj >> /Meta1268 Do /Length 16 >> q >> q q 0 w >> endstream 1 i /Meta542 Do endstream /F3 17 0 R >> /Subtype /Form 1494 0 obj /F3 17 0 R >> endstream /Length 54 >> q /Resources<< /Resources<< 1.005 0 0 1.006 102.382 852.936 cm /ProcSet[/PDF] Q Q >> Q [(Wri)-18(te th)-19(e sen)-23(tence a)-15(s an e)-22(quati)-18(on. /Length 12 q endstream q 1435 0 obj /Subtype /Form 0 G /Meta568 Do /Meta608 Do 16.469 5.203 TD endstream /FormType 1 ET /Meta548 Do /ProcSet[/PDF] >> /Resources<< >> /F3 12.131 Tf endstream 478 0 obj q 0 g 0 g 1.007 0 0 1.006 551.058 359.844 cm 84 0 obj << /Resources<< >> >> << /Length 54 Q q /BBox [0 0 88.214 16.44] (-) Tj /Type /XObject 1 i Q Q 192.472 5.203 TD 0 g /F4 24 0 R /Length 69 679.036 146.045 m 0 G >> /XHeight 447 >> /Length 342 >> q /ProcSet[/PDF] q q << endstream /Type /XObject /ProcSet[/PDF/Text] BT endstream >> /Meta1630 Do Q /Matrix [1 0 0 1 0 0] /Meta317 Do /Font << ET /Subtype /Form 1.007 0 0 1.007 130.989 893.588 cm 1 i Q ET >> ET >> 1 g /F3 12.131 Tf /ProcSet[/PDF] >> endobj /Resources<< q 26.957 5.203 TD q /Type /XObject stream >> 0 G q /Length 54 1 i 1 i 722.699 560.845 l /Length 69 Q 1.007 0 0 1.007 411.035 453.193 cm q /Type /XObject /BBox [0 0 88.214 16.44] 0 w >> /Meta1166 1184 0 R BT /ProcSet[/PDF/Text] /F4 24 0 R 1100 0 obj >> /BBox [0 0 15.59 16.44] /Meta555 Do q 0 g 0.737 w BT q /FormType 1 0 g BT 1.005 0 0 1.007 102.382 416.305 cm /I0 Do >> 1 i /Meta1640 1660 0 R 1 i 0 5.203 TD /F3 17 0 R /Font << /Type /XObject /ProcSet[/PDF/Text] 0 G endobj /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] q /Resources<< /Meta1613 Do q /FormType 1 /F3 12.131 Tf 243 0 obj /Meta188 Do q /FormType 1 >> q Questions 1 - 12 have students using inverse operations to solve one-step equations. q Q stream /Resources<< q >> 1.007 0 0 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